# Smallest Range II

Given an array A of integers, for each integer A[i] we need to choose **either x = -K or x = K**, and add x to A[i] **(only once)**.

After this process, we have some array B.

Return the smallest possible difference between the maximum value of B and the minimum value of B.

**Example 1:**
**Input: **A = [1], K = 0 **Output: **0 **Explanation**: B = [1]
**Example 2:**
**Input: **A = [0,10], K = 2 **Output: **6 **Explanation**: B = [2,8]
**Example 3:**
**Input: **A = [1,3,6], K = 3

**Output: **3 **Explanation**: B = [4,6,3]
**Note:**

1 <= A.length <= 10000

0 <= A[i] <= 10000

0 <= K <= 10000

class Solution {

public int smallestRangeII(int[] A, int K) {

int N = A.length;

Arrays.sort(A);

int ans = A[N-1] - A[0];

for (int i = 0; i < A.length - 1; ++i) {

int a = A[i], b = A[i+1];

int high = Math.max(A[N-1] - K, a + K);

int low = Math.min(A[0] + K, b - K);

ans = Math.min(ans, high - low);

}

return ans;

}

}