Given a balanced parentheses string S, compute the score of the string based on the following rule:
() has score 1
AB has score A + B, where A and B are balanced parentheses strings.
(A) has score 2 * A, where A is a balanced parentheses string.
Example 1:
Input: "()"Output: 1
Example 2:
Input: "(())"Output: 2
Example 3:
Input: "()()"Output: 2
Example 4:
Input: "(()(()))"Output: 6
Note:
S is a balanced parentheses string, containing only ( and ).
2 <= S.length <= 50
Solution:
class Solution {
public int scoreOfParentheses(String S) {
int ans=0,bal=0;
for(int i=0;i<S.length();i++)
{
if(S.charAt(i)=='(')
{
bal++;
}
else
{
bal--;
if(S.charAt(i-1)=='(')
ans+=Math.pow(2,bal);
}
}
return ans;
}
}
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