You are given an integer array nums and two integers limit and goal. The array nums has an interesting property that abs(nums[i]) <= limit.

Return the minimum number of elements you need to add to make the sum of the array equal to goal. The array must maintain its property that abs(nums[i]) <= limit.

Note that abs(x) equals x if x >= 0, and -x otherwise.

Example 1:

```
Input: nums = [1,-1,1], limit = 3, goal = -4
Output: 2
Explanation: You can add -2 and -3, then the sum of the array will be 1 - 1 + 1 - 2 - 3 = -4.
```

Example 2:

```
Input: nums = [1,-10,9,1], limit = 100, goal = 0
Output: 1
```

Constraints:

1 <= nums.length <= 105

1 <= limit <= 106

-limit <= nums[i] <= limit

-109 <= goal <= 109

Solution:

```
class Solution {
public int minElements(int[] nums, int limit, int goal) {
long sum = 0;
for(int num:nums)
{
sum+=num;
}
long diff = Math.abs(sum-goal);
return (int)(diff/limit)+(diff%limit>0?1:0);
}
}
```

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