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Get Maximum in Generated Array

You are given an integer n. An array nums of length n + 1 is generated in the following way:

• nums[0] = 0

• nums[1] = 1

• nums[2 * i] = nums[i] when 2 <= 2 * i <= n

• nums[2 * i + 1] = nums[i] + nums[i + 1] when 2 <= 2 * i + 1 <= n

Return the maximum integer in the array nums​​​.

Example 1:

```
Input: n = 7
Output: 3
Explanation:
According to the given rules:   nums[0] = 0
nums[1] = 1
nums[(1 * 2) = 2] = nums[1] = 1
nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2
nums[(2 * 2) = 4] = nums[2] = 1
nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3
nums[(3 * 2) = 6] = nums[3] = 2
nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3

Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is 3. ```

Example 2:

```Input: n = 2
Output: 1
Explanation: According to the given rules, the maximum between nums[0], nums[1], and nums[2] is 1. ```

Example 3:

```Input: n = 3
Output: 2
Explanation: According to the given rules, the maximum between nums[0], nums[1], nums[2], and nums[3] is 2. ```

Constraints:

• 0 <= n <= 100

Solution:

```class Solution {
public int getMaximumGenerated(int n) {
int[] nums=new int[n+1];
int max=0;
nums[0]=0;
if(n==0 || n==1)
return n;
nums[1]=1;

for(int i=2;i<=n;i++)
{
if(i%2==0)
{
nums[i]=nums[i/2];
}
else
nums[i]=nums[i/2]+nums[i/2+1];
max=Math.max(max,nums[i]);
}

return max;
}
}```