# Generate Random Point in a Circle

Given the radius and x-y positions of the center of a circle, write a function randPoint which generates a uniform random point in the circle. Note:

input and output values are in floating-point.

radius and x-y position of the center of the circle is passed into the class constructor.

a point on the circumference of the circle is considered to be in the circle.

randPoint returns a size 2 array containing x-position and y-position of the random point, in that order.

**Example 1:**

```
```**Input****:**** **["Solution","randPoint","randPoint","randPoint"] [[1,0,0],[],[],[]]
**Output****:**** **[null,[-0.72939,-0.65505],[-0.78502,-0.28626],[-0.83119,-0.19803]]

**Example 2:**

```
```**Input****:**** **["Solution","randPoint","randPoint","randPoint"] [[10,5,-7.5],[],[],[]]
**Output****:**** **[null,[11.52438,-8.33273],[2.46992,-16.21705],[11.13430,-12.42337]]

**Explanation of Input Syntax:**

The input is two lists: the subroutines called and their arguments. Solution's constructor has three arguments, the radius, x-position of the center, and y-position of the center of the circle. randPoint has no arguments. Arguments are always wrapped with a list, even if there aren't any.

**Solution:**

```
class Solution {
double r;
double x;
double y;
public Solution(double radius, double x_center, double y_center) {
this.r=radius;
this.x=x_center;
this.y=y_center;
}
public double[] randPoint() {
double minx = x-r;
double maxx = x+r;
double miny = y-r;
double maxy = y+r;
double[] result = new double[2];
result[0] = ((Math.random()*(maxx-minx))+minx);
result[1] = ((Math.random()*(maxy-miny))+miny);
while((result[0]-x)*(result[0]-x) + (result[1]-y)*(result[1]-y)>=r*r)
{
result[0] = ((Math.random()*(maxx-minx))+minx);
result[1] = ((Math.random()*(maxy-miny))+miny);
}
return result;
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(radius, x_center, y_center);
* double[] param_1 = obj.randPoint();
*/
```