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Check If All 1's Are at Least Length K Places Away

Updated: Jan 26, 2021

Given an array nums of 0s and 1s and an integer k, return True if all 1's are at least k places away from each other, otherwise return False.


Example 1:

Input: nums = [1,0,0,0,1,0,0,1], k = 2
Output: true
Explanation: Each of the 1s are at least 2 places away from each other.

Example 2:

Input: nums = [1,0,0,1,0,1], k = 2
Output: false
Explanation: The second 1 and third 1 are only one apart from each other.

Example 3:

Input: nums = [1,1,1,1,1], k = 0
Output: true

Example 4:

Input: nums = [0,1,0,1], k = 1
Output: true

Constraints:

  • 1 <= nums.length <= 105

  • 0 <= k <= nums.length

  • nums[i] is 0 or 1

Solution:


class Solution {
    public boolean kLengthApart(int[] nums, int k) {
        int count = nums.length+1;
        for(int n:nums)
        {
            if(n==1)
            {
                if(count<k) return false;
                count=0;
            }
            else
            {
                count++;
            }
                 
        }
        return true;
    }
}


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