# Check If All 1's Are at Least Length K Places Away

Updated: Jan 26, 2021

Given an array nums of 0s and 1s and an integer k, return True if all 1's are at least k places away from each other, otherwise return False.

**Example 1:**

**Input****:** nums = [1,0,0,0,1,0,0,1], k = 2
**Output****:** true
**Explanation****:** Each of the 1s are at least 2 places away from each other.

**Example 2:**

**Input****:** nums = [1,0,0,1,0,1], k = 2
**Output****:** false
**Explanation****:**** **The second 1 and third 1 are only one apart from each other.

**Example 3:**

**Input****:** nums = [1,1,1,1,1], k = 0
**Output****:** true

**Example 4:**

**Input****:** nums = [0,1,0,1], k = 1
**Output****:** true

**Constraints:**

1 <= nums.length <= 105

0 <= k <= nums.length

nums[i] is 0 or 1

**Solution:**

```
class Solution {
public boolean kLengthApart(int[] nums, int k) {
int count = nums.length+1;
for(int n:nums)
{
if(n==1)
{
if(count<k) return false;
count=0;
}
else
{
count++;
}
}
return true;
}
}
```