Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
Example:
Input: [1,2,3,null,5,null,4]
Output: [1, 3, 4]
Explanation:
1 <---
/ \
2 3 <---
\ \
5 4 <---
Solution:
class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> result = new ArrayList<Integer>();
Queue<TreeNode> queue = new LinkedList<>();
if(root==null) return result;
queue.offer(root);
while(!queue.isEmpty())
{
int size = queue.size();
for(int i=0;i<size;i++)
{
TreeNode currentNode = queue.poll();
if(i==0) result.add(currentNode.val);
if(currentNode.right!=null) queue.offer(currentNode.right);
if(currentNode.left!=null) queue.offer(currentNode.left);
}
}
return result;
}
}
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