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# Search in Rotated Sorted Array

Updated: Mar 25, 2021

There is an integer array nums sorted in ascending order (with distinct values).

Prior to being passed to your function, nums is rotated at an unknown pivot index k (0 <= k < nums.length) such that the resulting array is [nums[k], nums[k+1], ..., nums[n-1], nums, nums, ..., nums[k-1]] (0-indexed). For example, [0,1,2,4,5,6,7] might be rotated at pivot index 3 and become [4,5,6,7,0,1,2].

Given the array nums after the rotation and an integer target, return the index of target if it is in nums, or -1 if it is not in nums.

Example 1:

```Input: nums = [4,5,6,7,0,1,2], target = 0
Output: 4

```

Example 2:

```Input: nums = [4,5,6,7,0,1,2], target = 3
Output: -1

```

Example 3:

```Input: nums = , target = 0
Output: -1

```

Constraints:

• 1 <= nums.length <= 5000

• -104 <= nums[i] <= 104

• All values of nums are unique.

• nums is guaranteed to be rotated at some pivot.

• -104 <= target <= 104

Solution:

```class Solution {
public int search(int[] nums, int target) {
int left =0,right=nums.length-1;
int mid;

while(left<=right)
{
mid=(left+right)/2;

if(nums[mid]==target) return mid;
else if(nums[mid]>=nums[left])
{
if(target<=nums[mid] && target>=nums[left])
right = mid-1;
else
left=mid+1;
}
else
{
if(target>=nums[mid] && target<=nums[right])
left=mid+1;
else
right=mid-1;
}
}
return -1;
}
}```