# Ones and Zeroes

You are given an array of binary strings strs and two integers m and n.

Return *the size of the largest subset of strs such that there are at most* m 0

*'s and*n 1

*'s in the subset*.

A set x is a **subset** of a set y if all elements of x are also elements of y.

**Example 1:**

**Input****:** strs = ["10","0001","111001","1","0"], m = 5, n = 3
**Output****:** 4
**Explanation****:** The largest subset with at most 5 0's and 3 1's is {"10", "0001", "1", "0"}, so the answer is 4.
Other valid but smaller subsets include {"0001", "1"} and {"10", "1", "0"}.
{"111001"} is an invalid subset because it contains 4 1's, greater than the maximum of 3.

**Example 2:**

**Input****:** strs = ["10","0","1"], m = 1, n = 1
**Output****:** 2
**Explanation****:** The largest subset is {"0", "1"}, so the answer is 2.

**Constraints:**

1 <= strs.length <= 600

1 <= strs[i].length <= 100

strs[i] consists only of digits '0' and '1'.

1 <= m, n <= 100

**Solution:**

```
class Solution {
public int findMaxForm(String[] strs, int m, int n) {
int[][] dp=new int[m+1][n+1];
for(String s:strs)
{
int zeros=0,ones=0;
for(char c:s.toCharArray())
{
if(c=='0') zeros++;
else ones++;
}
for(int i=m;i>=zeros;i--)
{
for(int j=n;j>=ones;j--)
{
dp[i][j]= Math.max(dp[i][j],dp[i-zeros][j-ones]+1);
}
}
}
return dp[m][n];
}
}
```