Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

The number of elements initialized in nums1 and nums2 are m and n respectively. You may assume that nums1 has enough space (size that is equal to m + n) to hold additional elements from nums2.

Example 1:

```
Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
```

Example 2:

```
Input: nums1 = [1], m = 1, nums2 = [], n = 0
Output: [1]
```

Constraints:

0 <= n, m <= 200

1 <= n + m <= 200

nums1.length == m + n

nums2.length == n

-109 <= nums1[i], nums2[i] <= 109

Solution:

```
class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int first = m-1;
int second = n-1;
for(int i=m+n-1;i>=0;i--)
{
if(second<0) break;
if(first>=0 && nums1[first]>nums2[second])
{
nums1[i]=nums1[first];
first--;
}
else
{
nums1[i]=nums2[second];
second--;
}
}
}
}
```

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