Given an array arr of positive integers sorted in a strictly increasing order, and an integer k. Find the kth positive integer that is missing from this array. Example 1:

```
Input:
arr = [2,3,4,7,11],
k = 5
Output: 9
Explanation: The missing positive integers are [1,5,6,8,9,10,12,13,...]. The 5th missing positive integer is 9.
```

Example 2:

```
Input: arr = [1,2,3,4], k = 2
Output: 6
Explanation: The missing positive integers are [5,6,7,...]. The 2nd missing positive integer is 6.
```

Constraints:

1 <= arr.length <= 1000

1 <= arr[i] <= 1000

1 <= k <= 1000

arr[i] < arr[j] for 1 <= i < j <= arr.length

Solution:

```
class Solution {
public int findKthPositive(int[] arr, int k) {
Set<Integer> set = new HashSet<Integer>();
for(int a : arr)
{
set.add(a);
}
int start =1;
int Count = k;
while(Count>0)
{
if(set.contains(start))
{
start++;
}
else
{
start++;
Count--;
}
}
return start-1;
}
}
```

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